If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+24x+1300=0
a = 1; b = 24; c = +1300;
Δ = b2-4ac
Δ = 242-4·1·1300
Δ = -4624
Delta is less than zero, so there is no solution for the equation
| -14=2x-3(5x-17) | | 4x2-29x+45=0 | | 4(y/3)+9y=22 | | 41-2=-5(2n-8) | | -59=2x+7(x-20) | | (-1/16x)+3/2=0 | | (1-p)(1-p)=0.16 | | 7+2p=28 | | -1/16x+3/2=0 | | -3x=1/3(-9x+6) | | (5)m=35 | | 8(1.4x+3.4)=17 | | 27=(9)s | | X-6=1/2(x+5) | | 24=6x-3(4x+2) | | 2(2x+3)−2=5 | | 1/4=8^(3x+5) | | 2x+6(x-6)=92 | | h/6-20=-17 | | 4a^2=16+3a^2 | | (4x+3)+(6x-12)=180 | | 9x+45=36 | | 3(b-4)-5b=-2 | | 3(b-4)-5b=-2* | | 2j-11=3 | | 15=2d+5 | | 6x-60=-18 | | 9(8d+3)=23 | | 20x-50=30x | | X²-5x+6=x+x² | | 9x-1+x=49 | | -9g+-28=71 |